What are the solutions to the equation 3x^2-26x+35=0 ?

The solutions to the equation 3x^2-26x+35=0 are x=7,x= 5/3

Find the zeros of 3x^2-26x+35=0

The zeros of 3x^2-26x+35=0 are x=7,x= 5/3

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3 x^{2} - 26 x + 35 = 0

x = 7, x = \frac{5}{3}

Solution steps

3 x^{2} - 26 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 3 \cdot 35}{2 \cdot 3}

(- 26)^{2} - 4 \cdot 3 \cdot 35 = 16

x_{1, 2} = \frac{- ( - 26 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 26 ) - 16}{2 \cdot 3}

x = \frac{- ( - 26 ) + 16}{2 \cdot 3} : 7

x = \frac{- ( - 26 ) - 16}{2 \cdot 3} : \frac{5}{3}

The solutions to the quadratic equation are:

x = 7, x = \frac{5}{3}

- - 36

3 (x - 2) 2 - 37 = 20

(\frac{g ^{3}}{h ^{2}})^{5}

5^{- \frac{3}{2}}

\frac{11}{7} (- 8)^{\frac{2}{3}}

What are the solutions to the equation 3x^2-26x+35=0 ?
The solutions to the equation 3x^2-26x+35=0 are x=7,x= 5/3
Find the zeros of 3x^2-26x+35=0
The zeros of 3x^2-26x+35=0 are x=7,x= 5/3