What are the solutions to the equation x^2-13x+30=0 ?

The solutions to the equation x^2-13x+30=0 are x=10,x=3

Find the zeros of x^2-13x+30=0

The zeros of x^2-13x+30=0 are x=10,x=3

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x^{2} - 13 x + 30 = 0

x = 10, x = 3

Solution steps

x^{2} - 13 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 30 = 7

x_{1, 2} = \frac{- ( - 13 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 7}{2 \cdot 1}

x = \frac{- ( - 13 ) + 7}{2 \cdot 1} : 10

x = \frac{- ( - 13 ) - 7}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 10, x = 3

- 9 x + 10 > - 8

(z + 5)^{2} = - 13

x^{2} - 36 = 0

r^{2} - 12 r + 45 = 0

\frac{49}{c} \leq 14

What are the solutions to the equation x^2-13x+30=0 ?
The solutions to the equation x^2-13x+30=0 are x=10,x=3
Find the zeros of x^2-13x+30=0
The zeros of x^2-13x+30=0 are x=10,x=3