What is MLt^{-2}sin(kL^{-2}M^{-1}) ?

The solution to MLt^{-2}sin(kL^{-2}M^{-1}) is (LMsin(k/(L^2M)))/(t^2)

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simplify MLt^{-2}sin(kL^{-2}M^{-1})

simplify

M L t^{- 2} sin (k L^{- 2} M^{- 1})

\frac{L M sin ( \frac{k}{L ^{2} M} )}{t ^{2}}

Solution steps

M L t^{- 2} sin (k L^{- 2} M^{- 1})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= L \frac{1}{t ^{2}} M sin (L^{- 2} k M^{- 1})

Multiply

k L^{- 2} M^{- 1} : \frac{k}{L ^{2} M}

= L \frac{1}{t ^{2}} M sin (\frac{k}{L ^{2} M})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot M L sin ( \frac{k}{L ^{2} M} )}{t ^{2}}

Multiply:

1 \cdot M = M

= \frac{L M sin ( \frac{k}{L ^{2} M} )}{t ^{2}}

e^{- 0.356} \cdot (1^{0.6831})

- e^{- \frac{4}{5}}

12000000 (1 + 0.025)^{- 12}

a^{7} b^{7}

What is MLt^{-2}sin(kL^{-2}M^{-1}) ?
The solution to MLt^{-2}sin(kL^{-2}M^{-1}) is (LMsin(k/(L^2M)))/(t^2)