What is (1(-10)^{-5})^{400} ?

The solution to (1(-10)^{-5})^{400} is 1/(10^{2000)}

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simplify (1(-10)^{-5})^{400}

simplify

(1 (- 10)^{- 5})^{400}

\frac{1}{1 0 ^{2000}}

Solution steps

(1 \cdot (- 10)^{- 5})^{400}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(1 \cdot (- 10)^{- 5})^{400} = 1^{400} ((- 10)^{- 5})^{400}

= 1^{400} ((- 10)^{- 5})^{400}

1^{400} = 1

= 1 \cdot ((- 10)^{- 5})^{400}

Apply exponent rule:

(a^{b})^{c} = a^{b c}, a \geq 0

((- 10)^{- 5})^{400} = (- 10)^{- 5 \cdot 400}

= 1 \cdot (- 10)^{- 5 \cdot 400}

Multiply the numbers:

5 \cdot 400 = 2000

= 1 \cdot (- 10)^{- 2000}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(- 10)^{- 2000} = \frac{1}{( - 10 ) ^{2000}}

= 1 \cdot \frac{1}{( - 10 ) ^{2000}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 10)^{2000} = 1 0^{2000}

= 1 \cdot \frac{1}{1 0 ^{2000}}

Multiply:

1 \cdot \frac{1}{1 0 ^{2000}} = \frac{1}{1 0 ^{2000}}

= \frac{1}{1 0 ^{2000}}

3 e^{- 2 x}

\frac{t + 5}{t - 5}

\frac{( x - e ^{x} ) ^{2}}{x ^{2}}

5.5 \cdot (23.4 \cdot 1 0^{- 3})

e^{- 2 \cdot l n (4)}

What is (1(-10)^{-5})^{400} ?
The solution to (1(-10)^{-5})^{400} is 1/(10^{2000)}