What is (5^x4^y)*(3^x2^y) ?

The solution to (5^x4^y)*(3^x2^y) is 8^y*15^x

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simplify (5^x4^y)*(3^x2^y)

simplify

(5^{x} 4^{y}) \cdot (3^{x} 2^{y})

8^{y} \cdot 1 5^{x}

Solution steps

(5^{x} \cdot 4^{y}) (3^{x} \cdot 2^{y})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m}

5^{x} \cdot 3^{x} = (5 \cdot 3)^{x}

= 4^{y} \cdot 2^{y} (5 \cdot 3)^{x}

Multiply the numbers:

5 \cdot 3 = 15

= 4^{y} \cdot 2^{y} \cdot 1 5^{x}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m}

4^{y} \cdot 2^{y} = (4 \cdot 2)^{y}

= 1 5^{x} (4 \cdot 2)^{y}

Multiply the numbers:

4 \cdot 2 = 8

= 8^{y} \cdot 1 5^{x}

5347.7 \cdot 1 0^{- 7}

e^{- l n (3 x)}

5.1 \cdot 1 0^{- 3} \cdot 2

1.12 \cdot 1 0^{- 3} \cdot 40