What is x(x^2+1)(x+2)^2(x-2)^2 ?

The solution to x(x^2+1)(x+2)^2(x-2)^2 is x(x+2)^2(x-2)^2(x^2+1)

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simplify x(x^2+1)(x+2)^2(x-2)^2

simplify

x (x^{2} + 1) (x + 2)^{2} (x - 2)^{2}

x (x + 2)^{2} (x - 2)^{2} (x^{2} + 1)

Solution steps

x (x^{2} + 1) (x + 2)^{2} (x - 2)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 2)^{2} (x - 2)^{2} = ((x + 2) (x - 2))^{2}

= x (x^{2} + 1) ((x + 2) (x - 2))^{2}

((x + 2) (x - 2))^{2} = (x + 2)^{2} (x - 2)^{2}

= x (x^{2} + 1) (x + 2)^{2} (x - 2)^{2}

1.03529 \cdot 1 0^{- 6}

x x^{2} + x

1 \cdot 0. 9^{20} \cdot 1

8.85 \cdot 1 0^{- 9} \cdot π

e^{- l n ((\frac{1}{2 x ^{2}}) + c)}

What is x(x^2+1)(x+2)^2(x-2)^2 ?
The solution to x(x^2+1)(x+2)^2(x-2)^2 is x(x+2)^2(x-2)^2(x^2+1)