What is laplaccos(2t)e^{-3t}2 ?

The solution to laplaccos(2t)e^{-3t}2 is 4l^2e^{-3t}a^2pc^2ost

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simplify laplaccos(2t)e^{-3t}2

simplify

l a pl a ccos (2 t) e^{- 3 t} 2

4 l^{2} e^{- 3 t} a^{2} p c^{2} os t

Solution steps

l a pl a ccos (2 t) e^{- 3 t} \cdot 2

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= l a pl a ccos t e^{- 3 t} \cdot 2^{1 + 1}

Add the numbers:

1 + 1 = 2

= l a pl a ccos t e^{- 3 t} \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ll = l^{1 + 1}

= a p l^{1 + 1} a ccos t e^{- 3 t} \cdot 2^{2}

Add the numbers:

1 + 1 = 2

= a p l^{2} a ccos t e^{- 3 t} \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

= p l^{2} a^{1 + 1} ccos t e^{- 3 t} \cdot 2^{2}

Add the numbers:

1 + 1 = 2

= p l^{2} a^{2} ccos t e^{- 3 t} \cdot 2^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

cc = c^{1 + 1}

= p l^{2} a^{2} c^{1 + 1} os t e^{- 3 t} \cdot 2^{2}

Add the numbers:

1 + 1 = 2

= p l^{2} a^{2} c^{2} os t e^{- 3 t} \cdot 2^{2}

2^{2} = 4

= 4 l^{2} e^{- 3 t} a^{2} p c^{2} os t

2000 \cdot 2.7 1^{- 0.05 X}

e^{- \frac{j ^{4} π}{3}}

\frac{e ^{2 x}}{e ^{2 x + 1}}

3 (- 3 - x^{2}) 0.3 (- 3 - x^{2})

124342.6 \cdot (1 + 0.1)^{- 3}

What is laplaccos(2t)e^{-3t}2 ?
The solution to laplaccos(2t)e^{-3t}2 is 4l^2e^{-3t}a^2pc^2ost