What are the solutions to the equation x^2=108-3x ?

The solutions to the equation x^2=108-3x are x=9,x=-12

Find the zeros of x^2=108-3x

The zeros of x^2=108-3x are x=9,x=-12

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x^{2} = 108 - 3 x

x = 9, x = - 12

Solution steps

x^{2} = 108 - 3 x

Move

3 x

to the left side

x^{2} + 3 x = 108

Move

108

to the left side

x^{2} + 3 x - 108 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 108 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 108) = 21

x_{1, 2} = \frac{- 3 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 21}{2 \cdot 1}, x_{2} = \frac{- 3 - 21}{2 \cdot 1}

x = \frac{- 3 + 21}{2 \cdot 1} : 9

x = \frac{- 3 - 21}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 9, x = - 12

6 x - 3

3 (x - 3) - 14 = 2 (x - 7) + 8

24 - 4 x = 2 x

lo g_{16} (4) = y

3^{2} + x^{2} = 8^{2}

What are the solutions to the equation x^2=108-3x ?
The solutions to the equation x^2=108-3x are x=9,x=-12
Find the zeros of x^2=108-3x
The zeros of x^2=108-3x are x=9,x=-12