What is (5xy)2(2x^2y) ?

The solution to (5xy)2(2x^2y) is 20x^3y^2

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simplify (5xy)2(2x^2y)

simplify

(5 x y) 2 (2 x^{2} y)

20 x^{3} y^{2}

Solution steps

(5 x y) \cdot 2 (2 x^{2} y)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= 5 x y \cdot 2^{1 + 1} x^{2} y

Add the numbers:

1 + 1 = 2

= 5 x y \cdot 2^{2} x^{2} y

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x x^{2} = x^{1 + 2}

= 5 y \cdot 2^{2} x^{1 + 2} y

Add the numbers:

1 + 2 = 3

= 5 y \cdot 2^{2} x^{3} y

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

yy = y^{1 + 1}

= 5 \cdot 2^{2} x^{3} y^{1 + 1}

Add the numbers:

1 + 1 = 2

= 5 \cdot 2^{2} x^{3} y^{2}

2^{2} = 4

= 5 \cdot 4 x^{3} y^{2}

Multiply the numbers:

5 \cdot 4 = 20

= 20 x^{3} y^{2}

(4.32 \cdot 1 0^{- 7}) \cdot 3600

e^{- θt} \cdot cos (wt) u (t)

0.3 \cdot 2^{2}

2 e^{- 2 \cdot 0.5}

\frac{w ^{2}}{w ^{4}} d w