What is (y^bax^a)(xby^b) ?

The solution to (y^bax^a)(xby^b) is bay^{2b}x^{a+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (y^bax^a)(xby^b)

simplify

(y^{b} a x^{a}) (x b y^{b})

ba y^{2 b} x^{a + 1}

Solution steps

(y^{b} a x^{a}) (x b y^{b})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{b} y^{b} = y^{b + b}

= a x^{a} x b y^{b + b}

Add similar elements:

b + b = 2 b

= a x^{a} x b y^{2 b}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{a} x = x^{a + 1}

= a x^{a + 1} b y^{2 b}

e^{- \frac{x + a}{b}}

14 e^{- \frac{20}{100}}

\frac{d}{d x} (a^{x})

3.5 \cdot 1 0^{- 5} \cdot 50

50000 (1 + 0.01)^{- 6}