What are the solutions to the equation x^2-14x+85=0 ?

The solutions to the equation x^2-14x+85=0 are x=7+6i,x=7-6i

Find the zeros of x^2-14x+85=0

The zeros of x^2-14x+85=0 are x=7+6i,x=7-6i

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x^{2} - 14 x + 85 = 0

x = 7 + 6 i, x = 7 - 6 i

Solution steps

x^{2} - 14 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 85 : 12 i

x_{1, 2} = \frac{- ( - 14 ) \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 12 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 12 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 12 i}{2 \cdot 1} : 7 + 6 i

x = \frac{- ( - 14 ) - 12 i}{2 \cdot 1} : 7 - 6 i

The solutions to the quadratic equation are:

x = 7 + 6 i, x = 7 - 6 i

\frac{( 2 x - 7 )}{4} \leq \frac{1}{3}

16 x y^{2} + 28 x y + 8 y

x^{2} + 12 x = - 32

25 p^{2} - 40 p + 16

- 6 < x - 4 \leq 1

What are the solutions to the equation x^2-14x+85=0 ?
The solutions to the equation x^2-14x+85=0 are x=7+6i,x=7-6i
Find the zeros of x^2-14x+85=0
The zeros of x^2-14x+85=0 are x=7+6i,x=7-6i