What is 1.6*10^{-19}(3712) ?

The solution to 1.6*10^{-19}(3712) is (29)/(5^{20)*512}

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simplify 1.6*10^{-19}(3712)

simplify

1.6 \cdot 1 0^{- 19} (3712)

\frac{29}{5 ^{20} \cdot 512}

Decimal Notation

5.9392 E - 16

Solution steps

1.6 \cdot 1 0^{- 19} (3712)

Apply rule:

(a) = a

(3712) = 3712

= 1.6 \cdot 1 0^{- 19} \cdot 3712

Multiply the numbers:

1.6 \cdot 3712 = 5939.2

= 5939.2 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 5939.2

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 5939.2

\frac{1}{1 0 ^{19}} \cdot 5939.2 = \frac{5939.2}{1 0 ^{19}}

= \frac{5939.2}{1 0 ^{19}}

\frac{5939.2}{1 0 ^{19}} = \frac{59392}{10 \cdot 1 0 ^{19}}

= \frac{59392}{10 \cdot 1 0 ^{19}}

10 \cdot 1 0^{19} = 1 0^{20}

= \frac{59392}{1 0 ^{20}}

Factor

59392 : 2^{11} \cdot 29

= \frac{2 ^{11} \cdot 29}{1 0 ^{20}}

Factor

1 0^{20} : 2^{20} \cdot 5^{20}

= \frac{2 ^{11} \cdot 29}{2 ^{20} \cdot 5 ^{20}}

\frac{2 ^{11}}{2 ^{20}} = \frac{1}{2 ^{9}}

= \frac{29}{2 ^{9} \cdot 5 ^{20}}

2^{9} = 512

= \frac{29}{5 ^{20} \cdot 512}

(1.7) (1 0^{- 5}) (0.008)

(- x + 20) e^{- 4 x}

25 \cdot 2. 7^{- 0.01 \cdot 10}

(2 x - 7 y^{6} z^{3}) \cdot (3 x) 3

2.027 \cdot 1 0^{- 3} \cdot 4.79

What is 1.6*10^{-19}(3712) ?
The solution to 1.6*10^{-19}(3712) is (29)/(5^{20)*512}