simplify ba^2ab^2

Solution

simplify

b a^{2^{\circ}} a b^{2}

b^{3} a^{1 + 2^{\circ}}

Solution steps

b a^{2^{\circ}} a b^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b b^{2} = b^{1 + 2}

= a^{2^{\circ}} a b^{1 + 2}

Add the numbers:

1 + 2 = 3

= a^{2^{\circ}} a b^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a^{2^{\circ}} a = a^{2^{\circ} + 1}

= a^{2^{\circ} + 1} b^{3}

t^{3} e^{- a t}

(a + b + x + y) (a^{2} b^{2})

4 t (4 t^{3})

999.9999800000000 \dots (4 \cdot 1 0^{- 3})