What is the derivative of sqrt(y-x^2+4) ?

The derivative of sqrt(y-x^2+4) is (-2x+\frac{dy)/(dx)}{2sqrt(y-x^2+4)}

What is the first derivative of sqrt(y-x^2+4) ?

The first derivative of sqrt(y-x^2+4) is (-2x+\frac{dy)/(dx)}{2sqrt(y-x^2+4)}

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Popular >

\frac{d}{d x} (y - x^{2} + 4)

\frac{- 2 x + \frac{d y}{d x}}{2 y - x ^{2} + 4}

Solution steps

\frac{d}{d x} (y - x^{2} + 4)

Apply the chain rule:

\frac{1}{2 y - x ^{2} + 4} \frac{d}{d x} (y - x^{2} + 4)

= \frac{1}{2 y - x ^{2} + 4} \frac{d}{d x} (y - x^{2} + 4)

\frac{d}{d x} (y - x^{2} + 4) = - 2 x + \frac{d y}{d x}

= \frac{1}{2 y - x ^{2} + 4} (- 2 x + \frac{d y}{d x})

Simplify

\frac{1}{2 y - x ^{2} + 4} (- 2 x + \frac{d y}{d x}) : \frac{- 2 x + \frac{d y}{d x}}{2 y - x ^{2} + 4}

= \frac{- 2 x + \frac{d y}{d x}}{2 y - x ^{2} + 4}

(2 g h^{5}) 2

7.5 x 1 0^{- 5}

- 4.5 \cdot 1 0^{- 10} \cdot 415

7.5 x 1 0^{- 2}

36.5 \cdot 1.602 \cdot 1 0^{- 19}

What is the derivative of sqrt(y-x^2+4) ?
The derivative of sqrt(y-x^2+4) is (-2x+\frac{dy)/(dx)}{2sqrt(y-x^2+4)}
What is the first derivative of sqrt(y-x^2+4) ?
The first derivative of sqrt(y-x^2+4) is (-2x+\frac{dy)/(dx)}{2sqrt(y-x^2+4)}