What are the solutions to the equation -24=48-2(x+4)^2 ?

The solutions to the equation -24=48-2(x+4)^2 are x=2,x=-10

Find the zeros of -24=48-2(x+4)^2

The zeros of -24=48-2(x+4)^2 are x=2,x=-10

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- 24 = 48 - 2 (x + 4)^{2}

x = 2, x = - 10

Solution steps

- 24 = 48 - 2 (x + 4)^{2}

Switch sides

48 - 2 (x + 4)^{2} = - 24

Move

48

to the right side

- 2 (x + 4)^{2} = - 72

Divide both sides by

- 2

(x + 4)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 36 : x = 2

Solve

x + 4 = - 36 : x = - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

1 2^{2} + b^{2} = 1 5^{2}

∣ 4 x - 7 ∣ + 3 = 7

3 x^{2} + x = 10

(a - 3 b) (a + 2 b) + 5 a (a + 2 b)

3 (4 x - 1) \geq 15 x

What are the solutions to the equation -24=48-2(x+4)^2 ?
The solutions to the equation -24=48-2(x+4)^2 are x=2,x=-10
Find the zeros of -24=48-2(x+4)^2
The zeros of -24=48-2(x+4)^2 are x=2,x=-10