What are the solutions to the equation 3x^2+x=10 ?

The solutions to the equation 3x^2+x=10 are x= 5/3 ,x=-2

Find the zeros of 3x^2+x=10

The zeros of 3x^2+x=10 are x= 5/3 ,x=-2

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3 x^{2} + x = 10

x = \frac{5}{3}, x = - 2

Solution steps

3 x^{2} + x = 10

Move

10

to the left side

3 x^{2} + x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 10) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 3}, x_{2} = \frac{- 1 - 11}{2 \cdot 3}

x = \frac{- 1 + 11}{2 \cdot 3} : \frac{5}{3}

x = \frac{- 1 - 11}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 2

(a - 3 b) (a + 2 b) + 5 a (a + 2 b)

3 (4 x - 1) \geq 15 x

\frac{π}{3} - \frac{π}{2}

9.24 (0.7 a + 1.7) = 9.39 a + 33.24

x \cdot x^{\frac{3}{2}}

What are the solutions to the equation 3x^2+x=10 ?
The solutions to the equation 3x^2+x=10 are x= 5/3 ,x=-2
Find the zeros of 3x^2+x=10
The zeros of 3x^2+x=10 are x= 5/3 ,x=-2