What is f(x,y)(x^2+y^2)e^{-x} ?

The solution to f(x,y)(x^2+y^2)e^{-x} is 1/(e^x)f(,xy)(x^2+y^2)

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simplify f(x,y)(x^2+y^2)e^{-x}

simplify

f (x, y) (x^{2} + y^{2}) e^{- x}

\frac{1}{e ^{x}} f (, x y) (x^{2} + y^{2})

Solution steps

f (x, y) (x^{2} + y^{2}) e^{- x}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{x}} f (, x y) (x^{2} + y^{2})

(x - 3) (x + 2) (x - 7)

\frac{( x ) ^{2}}{( x + 8 ) ^{2}}

(s + t)^{2} (s - t)^{2}

e^{- 0.0012 \cdot 150}

f^{- 1} (1 - ln (x - 2))

What is f(x,y)(x^2+y^2)e^{-x} ?
The solution to f(x,y)(x^2+y^2)e^{-x} is 1/(e^x)f(,xy)(x^2+y^2)