What are the solutions to the equation (7x+5)^2=14 ?

The solutions to the equation (7x+5)^2=14 are x=(sqrt(14)-5)/7 ,x=(-sqrt(14)-5)/7

Find the zeros of (7x+5)^2=14

The zeros of (7x+5)^2=14 are x=(sqrt(14)-5)/7 ,x=(-sqrt(14)-5)/7

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(7 x + 5)^{2} = 14

x = \frac{14 - 5}{7}, x = \frac{- 14 - 5}{7}

Decimal Notation

x = - 0.17976 \dots, x = - 1.24880 \dots

Solution steps

(7 x + 5)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 5 = 14 : x = \frac{14 - 5}{7}

Solve

7 x + 5 = - 14 : x = \frac{- 14 - 5}{7}

The solutions to the quadratic equation are:

x = \frac{14 - 5}{7}, x = \frac{- 14 - 5}{7}

(2 y + 5) (y - 4) = 0

x^{2} = 21 x

(7 x - 2)^{2} = 49

22 = - 2 u

3 x^{2} - 32 x + 64

What are the solutions to the equation (7x+5)^2=14 ?
The solutions to the equation (7x+5)^2=14 are x=(sqrt(14)-5)/7 ,x=(-sqrt(14)-5)/7
Find the zeros of (7x+5)^2=14
The zeros of (7x+5)^2=14 are x=(sqrt(14)-5)/7 ,x=(-sqrt(14)-5)/7