What is simplify-e^{-ln(-1/x+c)} ?

The solution to simplify-e^{-ln(-1/x+c)} is -x/(cx-1)

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simplify-e^{-ln(-1/x+c)}

simplify

- e^{- l n (- \frac{1}{x} + c)}

- \frac{x}{c x - 1}

Solution steps

- e^{- l n (- \frac{1}{x} + c)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= - \frac{1}{e ^{l n (- \frac{1}{x} + c)}}

e^{l n (- \frac{1}{x} + c)} = \frac{- 1 + c x}{x}

= - \frac{1}{\frac{c x - 1}{x}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= - \frac{x}{c x - 1}

t e^{- t} u (t) \cdot e^{- t} u

4.62 \cdot 1 0^{- 2}

(1.6 m^{3} n) (0.8 m^{2} n^{3})

5 e^{- 1.612}

(4 x - 8) e^{- 5 x}

What is simplify-e^{-ln(-1/x+c)} ?
The solution to simplify-e^{-ln(-1/x+c)} is -x/(cx-1)