What are the solutions to the equation 2(x+5)^2=40 ?

The solutions to the equation 2(x+5)^2=40 are x=2sqrt(5)-5,x=-2sqrt(5)-5

Find the zeros of 2(x+5)^2=40

The zeros of 2(x+5)^2=40 are x=2sqrt(5)-5,x=-2sqrt(5)-5

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2 (x + 5)^{2} = 40

x = 25 - 5, x = - 25 - 5

Decimal Notation

x = - 0.52786 \dots, x = - 9.47213 \dots

Solution steps

2 (x + 5)^{2} = 40

Divide both sides by

2

(x + 5)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 20 : x = 25 - 5

Solve

x + 5 = - 20 : x = - 25 - 5

The solutions to the quadratic equation are:

x = 25 - 5, x = - 25 - 5

a^{n} + a^{n + 1}

4 9^{\frac{5}{2}}

\frac{( ( 0 ) ^{2} + 1 ) ^{5} + 5 ( 0 ) ^{2}}{10} + c = 0

p - 18 = 3

b^{2} - 2 b - 63

What are the solutions to the equation 2(x+5)^2=40 ?
The solutions to the equation 2(x+5)^2=40 are x=2sqrt(5)-5,x=-2sqrt(5)-5
Find the zeros of 2(x+5)^2=40
The zeros of 2(x+5)^2=40 are x=2sqrt(5)-5,x=-2sqrt(5)-5