What is ((e^{-3x})+(e^{7x}))^{-11} ?

The solution to ((e^{-3x})+(e^{7x}))^{-11} is 1/((e^{-3x)+e^{7x})^{11}}

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simplify ((e^{-3x})+(e^{7x}))^{-11}

simplify

((e^{- 3 x}) + (e^{7 x}))^{- 11}

\frac{1}{( e ^{- 3 x} + e ^{7 x} ) ^{11}}

Solution steps

((e^{- 3 x}) + (e^{7 x}))^{- 11}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( e ^{- 3 x} + e ^{7 x} ) ^{11}}

0.5 \cdot 1.0 1^{- 0.167}

(5)^{x}

2.505 \cdot 1 0^{- 5}

(4 x^{7}) (2 x^{3})

(2 a^{2} b) (a b^{4})

What is ((e^{-3x})+(e^{7x}))^{-11} ?
The solution to ((e^{-3x})+(e^{7x}))^{-11} is 1/((e^{-3x)+e^{7x})^{11}}