What is (0.2)^2*Z^{-2} ?

The solution to (0.2)^2*Z^{-2} is 1/(25Z^2)

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simplify (0.2)^2*Z^{-2}

simplify

(0.2)^{2} \cdot Z^{- 2}

\frac{1}{25 Z ^{2}}

Solution steps

0. 2^{2} Z^{- 2}

0. 2^{2} = 0.04

= 0.04 Z^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

Z^{- 2} = \frac{1}{Z ^{2}}

= 0.04 \cdot \frac{1}{Z ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{0.04 \cdot 1}{Z ^{2}}

Multiply the numbers:

0.04 \cdot 1 = 0.04

= \frac{0.04}{Z ^{2}}

Simplify

\frac{0.04}{Z ^{2}} : \frac{4}{100 Z ^{2}}

= \frac{4}{100 Z ^{2}}

Cancel the numbers:

\frac{4}{100} = \frac{1}{25}

= \frac{1}{25 Z ^{2}}

e^{- \frac{1}{2} x^{2} = k}

(e^{2 x^{2}})^{- 1}

e^{- (0.031) (20)}

((\frac{2}{3})^{'})^{- 3}

e^{2} \cdot e^{2 x + 1}