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Popular >

simplify e^{-ln|1+y^2|}

Solution

simplify

e^{- l n ∣ 1 + y^{2} ∣}

Solution

\frac{1}{∣ y ^{2} + 1 ∣}

Solution steps

e^{- l n ∣ 1 + y^{2} ∣}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n ∣ 1 + y^{2} ∣}}

e^{l n ∣ 1 + y^{2} ∣} = 1 + y^{2}

= \frac{1}{∣ 1 + y ^{2} ∣}

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Frequently Asked Questions (FAQ)

What is e^{-ln|1+y^2|} ?
The solution to e^{-ln|1+y^2|} is 1/(|y^2+1|)