What is (6+2i)/(3-i) ?

The solution to (6+2i)/(3-i) is 8/5+6/5 i

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simplify (6+2i)/(3-i)

simplify

\frac{6 + 2 i}{3 - i}

\frac{8}{5} + \frac{6}{5} i

Solution steps

\frac{6 + 2 i}{3 - i}

Multiply by the conjugate

\frac{3 + i}{3 + i}

= \frac{( 6 + 2 i ) ( 3 + i )}{( 3 - i ) ( 3 + i )}

Simplify

\frac{( 6 + 2 i ) ( 3 + i )}{( 3 - i ) ( 3 + i )} : \frac{16 + 12 i}{10}

= \frac{16 + 12 i}{10}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{16}{10} + \frac{12}{10} i

Simplify

\frac{16}{10} + \frac{12}{10} i : \frac{8}{5} + \frac{6}{5} i

= \frac{8}{5} + \frac{6}{5} i

\frac{2 ^{8}}{2 ^{3}}

12 8^{\frac{5}{7}}

3 ∣ 2 x - 3 ∣ = 3

\frac{3 w + 8}{2} = 29 - \frac{7 w + 9}{5}

lo g_{8} (12) = x - 2