What is ((3^{-2})^3)^{-4} ?

The solution to ((3^{-2})^3)^{-4} is 3^{24}

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simplify ((3^{-2})^3)^{-4}

simplify

((3^{- 2})^{3})^{- 4}

3^{24}

Decimal Notation

282429536481

Solution steps

((3^{- 2})^{3})^{- 4}

(3^{- 2})^{3} : 3^{- 6}

= (3^{- 6})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( 3 ^{- 6} ) ^{4}}

(3^{- 6})^{4} : 3^{- 24}

= \frac{1}{3 ^{- 24}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

3^{- 24} = \frac{1}{3 ^{24}}

= \frac{1}{\frac{1}{3 ^{24}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{3 ^{24}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 3^{24}

(e^{\frac{5 π}{4}})^{5}

666.536 \cdot 1 0^{- 1}

0.011411 \cdot 1 1^{- 0.35828}

\frac{q ^{m}}{p ^{m}}

(1 + 0.5)^{2} \cdot (1 - 0.5)^{2}