What is 1.602x10^{(-19)} ?

The solution to 1.602x10^{(-19)} is (1.602x)/(10^{19)}

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simplify 1.602x10^{(-19)}

simplify

1.602 x 1 0^{(- 19)}

\frac{1.602 x}{1 0 ^{19}}

Solution steps

1.602 x \cdot 1 0^{- 19}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= 1.602 x \frac{1}{1 0 ^{19}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1.602 x \cdot 1}{1 0 ^{19}}

Multiply the numbers:

1.602 \cdot 1 = 1.602

= \frac{1.602 x}{1 0 ^{19}}

e^{- 2} \cdot 2^{100}

\frac{e ^{t}}{e ^{t^{3}}}

(1.6 \cdot 1 0^{- 19}) (- 0.822)

4 - x \cdot x^{2} + 9

t \cdot e^{a t} u (t)

What is 1.602x10^{(-19)} ?
The solution to 1.602x10^{(-19)} is (1.602x)/(10^{19)}