What are the solutions to the equation m^2+2m+5=0 ?

The solutions to the equation m^2+2m+5=0 are m=-1+2i,m=-1-2i

Find the zeros of m^2+2m+5=0

The zeros of m^2+2m+5=0 are m=-1+2i,m=-1-2i

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m^{2} + 2 m + 5 = 0

m = - 1 + 2 i, m = - 1 - 2 i

Solution steps

m^{2} + 2 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

m_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, m_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

m = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

m = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

m = - 1 + 2 i, m = - 1 - 2 i

2 - 16

\frac{1}{7} s = \frac{5}{7}

(x - 8)^{2}

(x^{2} - 14)^{2} - 8 (x^{2} - 14) - 20

\frac{3}{2 + 4 i}

What are the solutions to the equation m^2+2m+5=0 ?
The solutions to the equation m^2+2m+5=0 are m=-1+2i,m=-1-2i
Find the zeros of m^2+2m+5=0
The zeros of m^2+2m+5=0 are m=-1+2i,m=-1-2i