What are the solutions to the equation 2x^2+3x-8=0 ?

The solutions to the equation 2x^2+3x-8=0 are x=(-3+sqrt(73))/4 ,x=(-3-sqrt(73))/4

Find the zeros of 2x^2+3x-8=0

The zeros of 2x^2+3x-8=0 are x=(-3+sqrt(73))/4 ,x=(-3-sqrt(73))/4

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2 x^{2} + 3 x - 8 = 0

x = \frac{- 3 + 73}{4}, x = \frac{- 3 - 73}{4}

Decimal Notation

x = 1.38600 \dots, x = - 2.88600 \dots

Solution steps

2 x^{2} + 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 8) = 73

x_{1, 2} = \frac{- 3 \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 73}{2 \cdot 2}, x_{2} = \frac{- 3 - 73}{2 \cdot 2}

x = \frac{- 3 + 73}{2 \cdot 2} : \frac{- 3 + 73}{4}

x = \frac{- 3 - 73}{2 \cdot 2} : \frac{- 3 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 73}{4}, x = \frac{- 3 - 73}{4}

\frac{10}{- \frac{5}{2}} = \frac{- \frac{5}{2} + 9}{- \frac{5}{2} - 4}

- 2 < 2 - 2 x \leq 14

\frac{2 ^{2 n} - 2 ^{n - 1}}{2 ^{n} - 2 ^{- 1}}

6 x^{2} - 3 x - 9

0.0016

What are the solutions to the equation 2x^2+3x-8=0 ?
The solutions to the equation 2x^2+3x-8=0 are x=(-3+sqrt(73))/4 ,x=(-3-sqrt(73))/4
Find the zeros of 2x^2+3x-8=0
The zeros of 2x^2+3x-8=0 are x=(-3+sqrt(73))/4 ,x=(-3-sqrt(73))/4