What is 3e^{-cos(x)}e^{cos(x)} ?

The solution to 3e^{-cos(x)}e^{cos(x)} is 3

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simplify 3e^{-cos(x)}e^{cos(x)}

simplify

3 e^{- c o s (x)} e^{c o s (x)}

3

Solution steps

3 e^{- c o s (x)} e^{c o s (x)}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- c o s (x)} e^{c o s (x)} = e^{- c o s (x) + c o s (x)}

= 3 e^{- c o s (x) + c o s (x)}

Add similar elements:

- cos (x) + cos (x) = 0

= 3 e^{0}

Apply rule

a^{0} = 1, a \neq = 0

e^{0} = 1

= 3 \cdot 1

Multiply the numbers:

3 \cdot 1 = 3

= 3

\frac{a ^{10}}{b ^{10}}

x^{n} + 1 x^{n} - 1

0.5 e^{- 0.00244 (t)}

0.714769456 e^{- 0.0001 (0)}