What are the solutions to the equation 6x^2+13x=28 ?

The solutions to the equation 6x^2+13x=28 are x= 4/3 ,x=-7/2

Find the zeros of 6x^2+13x=28

The zeros of 6x^2+13x=28 are x= 4/3 ,x=-7/2

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6 x^{2} + 13 x = 28

x = \frac{4}{3}, x = - \frac{7}{2}

Decimal Notation

x = 1.33333 \dots, x = - 3.5

Solution steps

6 x^{2} + 13 x = 28

Move

28

to the left side

6 x^{2} + 13 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 ( - 28 )}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 (- 28) = 29

x_{1, 2} = \frac{- 13 \pm 29}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 13 + 29}{2 \cdot 6}, x_{2} = \frac{- 13 - 29}{2 \cdot 6}

x = \frac{- 13 + 29}{2 \cdot 6} : \frac{4}{3}

x = \frac{- 13 - 29}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{7}{2}

9 \cdot 15

\frac{3}{5 + 6 i}

9 f = 21 (12 f - 2)

- 75 x + 57 = - 75 x + 57

\frac{13 x - 6}{5 x - 3} \leq 3

What are the solutions to the equation 6x^2+13x=28 ?
The solutions to the equation 6x^2+13x=28 are x= 4/3 ,x=-7/2
Find the zeros of 6x^2+13x=28
The zeros of 6x^2+13x=28 are x= 4/3 ,x=-7/2