What is e^{3x}(3)(3cos(4cos(2x))) ?

The solution to e^{3x}(3)(3cos(4cos(2x))) is 9e^{3x}cos(4cos(2x))

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simplify e^{3x}(3)(3cos(4cos(2x)))

simplify

e^{3 x} (3) (3 cos (4 cos (2 x)))

9 e^{3 x} cos (4 cos (2 x))

Solution steps

e^{3 x} (3) (3 cos (4 cos (2 x)))

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

3 \cdot 3 = 3^{1 + 1}

= e^{3 x} \cdot 3^{1 + 1} cos (4 cos (2 x))

Add the numbers:

1 + 1 = 2

= e^{3 x} \cdot 3^{2} cos (4 cos (2 x))

3^{2} = 9

= 9 e^{3 x} cos (4 cos (2 x))

6.73 \cdot 1 0^{- 6}

7.379 (1 0^{- 4}) (10 0^{3}) 19.3

(8.04 \cdot 1 0^{- 4}) (231.8)

- 8 x^{6} (\frac{1}{4} x^{8})

What is e^{3x}(3)(3cos(4cos(2x))) ?
The solution to e^{3x}(3)(3cos(4cos(2x))) is 9e^{3x}cos(4cos(2x))