What are the solutions to the equation 35n^2+22n+3=0 ?

The solutions to the equation 35n^2+22n+3=0 are n=-1/5 ,n=-3/7

Find the zeros of 35n^2+22n+3=0

The zeros of 35n^2+22n+3=0 are n=-1/5 ,n=-3/7

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35 n^{2} + 22 n + 3 = 0

n = - \frac{1}{5}, n = - \frac{3}{7}

Decimal Notation

n = - 0.2, n = - 0.42857 \dots

Solution steps

35 n^{2} + 22 n + 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 35 \cdot 3}{2 \cdot 35}

2 2^{2} - 4 \cdot 35 \cdot 3 = 8

n_{1, 2} = \frac{- 22 \pm 8}{2 \cdot 35}

Separate the solutions

n_{1} = \frac{- 22 + 8}{2 \cdot 35}, n_{2} = \frac{- 22 - 8}{2 \cdot 35}

n = \frac{- 22 + 8}{2 \cdot 35} : - \frac{1}{5}

n = \frac{- 22 - 8}{2 \cdot 35} : - \frac{3}{7}

The solutions to the quadratic equation are:

n = - \frac{1}{5}, n = - \frac{3}{7}

4 x^{2} y^{2} - 4 x^{2} - 49 y^{2} + 49

\frac{3}{5} x = 10

x^{2} - 6 x - 5 = 0

\frac{7 π}{6} - 2 π

\frac{4}{2 + 2} + \frac{1}{3 - 2 2}

What are the solutions to the equation 35n^2+22n+3=0 ?
The solutions to the equation 35n^2+22n+3=0 are n=-1/5 ,n=-3/7
Find the zeros of 35n^2+22n+3=0
The zeros of 35n^2+22n+3=0 are n=-1/5 ,n=-3/7