What is (xln(x^2-x+2))^{-3} ?

The solution to (xln(x^2-x+2))^{-3} is 1/(x^3ln^3(x^2-x+2))

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simplify (xln(x^2-x+2))^{-3}

simplify

(x ln (x^{2} - x + 2))^{- 3}

\frac{1}{x ^{3} ln ^{3} ( x ^{2} - x + 2 )}

Solution steps

(x ln (x^{2} - x + 2))^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( x ln ( x ^{2} - x + 2 ) ) ^{3}}

(x ln (x^{2} - x + 2))^{3} = x^{3} ln^{3} (x^{2} - x + 2)

= \frac{1}{x ^{3} ln ^{3} ( x ^{2} - x + 2 )}

(e^{- \frac{π}{11}})^{10}

F^{- 1} (G (0))

C^{6} H^{16} O^{6}

5.5 \cdot 1 0^{- 11}

69.444 \cdot 1 0^{- 3}

What is (xln(x^2-x+2))^{-3} ?
The solution to (xln(x^2-x+2))^{-3} is 1/(x^3ln^3(x^2-x+2))