What are the solutions to the equation 3x^2-2x-7=0 ?

The solutions to the equation 3x^2-2x-7=0 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3

Find the zeros of 3x^2-2x-7=0

The zeros of 3x^2-2x-7=0 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3

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3 x^{2} - 2 x - 7 = 0

x = \frac{1 + 22}{3}, x = \frac{1 - 22}{3}

Decimal Notation

x = 1.89680 \dots, x = - 1.23013 \dots

Solution steps

3 x^{2} - 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 7) = 222

x_{1, 2} = \frac{- ( - 2 ) \pm 2 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 22}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 2 22}{2 \cdot 3}

x = \frac{- ( - 2 ) + 2 22}{2 \cdot 3} : \frac{1 + 22}{3}

x = \frac{- ( - 2 ) - 2 22}{2 \cdot 3} : \frac{1 - 22}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 22}{3}, x = \frac{1 - 22}{3}

1 6^{- 1.5}

6 x^{2} - 41 x - 7

(3 (\frac{9}{7}) + 3) + (4 (\frac{9}{7}) - 12) - 180 = A

e^{-, at}

\frac{x - 4}{x - 3} < 0

What are the solutions to the equation 3x^2-2x-7=0 ?
The solutions to the equation 3x^2-2x-7=0 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3
Find the zeros of 3x^2-2x-7=0
The zeros of 3x^2-2x-7=0 are x=(1+sqrt(22))/3 ,x=(1-sqrt(22))/3