What is (x+1)^{(2)}(x-1)^{(2)} ?

The solution to (x+1)^{(2)}(x-1)^{(2)} is (x+1)^2(x-1)^2

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simplify (x+1)^{(2)}(x-1)^{(2)}

simplify

(x + 1)^{(2)} (x - 1)^{(2)}

(x + 1)^{2} (x - 1)^{2}

Solution steps

(x + 1)^{(2)} (x - 1)^{(2)}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 1)^{2} (x - 1)^{2} = ((x + 1) (x - 1))^{2}

= ((x + 1) (x - 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x + 1)^{2} (x - 1)^{2}

2.38 \cdot 1 0^{- 1}

238000 x (3.827 x 1 0^{26})

\frac{4.3}{37.5} \cdot 1 0^{- 3}

What is (x+1)^{(2)}(x-1)^{(2)} ?
The solution to (x+1)^{(2)}(x-1)^{(2)} is (x+1)^2(x-1)^2