What is (6.02x10^{23})x(5.99x10^{-24}) ?

The solution to (6.02x10^{23})x(5.99x10^{-24}) is (36.0598x^3)/(10)

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simplify (6.02x10^{23})x(5.99x10^{-24})

simplify

(6.02 x 1 0^{23}) x (5.99 x 1 0^{- 24})

\frac{36.0598 x ^{3}}{10}

Solution steps

(6.02 x \cdot 1 0^{23}) x (5.99 x \cdot 1 0^{- 24})

Simplify

5.99 x \cdot 1 0^{- 24} : \frac{5.99 x}{1 0 ^{24}}

= 6.02 x \cdot 1 0^{23} x \frac{5.99 x}{1 0 ^{24}}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= 6.02 x^{2} \cdot 1 0^{23} \cdot \frac{5.99 x}{1 0 ^{24}}

= 1 0^{23} \cdot 6.02 x^{2} \frac{5.99 x}{1 0 ^{24}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 0 ^{23} \cdot 6.02 x ^{2} \cdot 5.99 x}{1 0 ^{24}}

Cancel

\frac{1 0 ^{23} \cdot 6.02 x ^{2} \cdot 5.99 x}{1 0 ^{24}} : \frac{6.02 x ^{2} \cdot 5.99 x}{10}

= \frac{6.02 x ^{2} \cdot 5.99 x}{10}

Simplify

6.02 x^{2} \cdot 5.99 x : 36.0598 x^{3}

= \frac{36.0598 x ^{3}}{10}

e^{2} \cdot e^{2 x}

14 e f^{428} e^{3} f

(e^{x^{2}})^{n - 1}

e^{a} \cdot e \cdot b

What is (6.02x10^{23})x(5.99x10^{-24}) ?
The solution to (6.02x10^{23})x(5.99x10^{-24}) is (36.0598x^3)/(10)