What are the solutions to the equation 10x^2+23x-21=0 ?

The solutions to the equation 10x^2+23x-21=0 are x= 7/10 ,x=-3

Find the zeros of 10x^2+23x-21=0

The zeros of 10x^2+23x-21=0 are x= 7/10 ,x=-3

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10 x^{2} + 23 x - 21 = 0

x = \frac{7}{10}, x = - 3

Decimal Notation

x = 0.7, x = - 3

Solution steps

10 x^{2} + 23 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 10 ( - 21 )}{2 \cdot 10}

2 3^{2} - 4 \cdot 10 (- 21) = 37

x_{1, 2} = \frac{- 23 \pm 37}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 23 + 37}{2 \cdot 10}, x_{2} = \frac{- 23 - 37}{2 \cdot 10}

x = \frac{- 23 + 37}{2 \cdot 10} : \frac{7}{10}

x = \frac{- 23 - 37}{2 \cdot 10} : - 3

The solutions to the quadratic equation are:

x = \frac{7}{10}, x = - 3

\frac{x}{5} \geq - 2

9 r^{4} - 121 v^{2}

14 x + 2 = 9 x - 3

\frac{6}{5} \cdot 3

x^{2} - 13 x + 40

What are the solutions to the equation 10x^2+23x-21=0 ?
The solutions to the equation 10x^2+23x-21=0 are x= 7/10 ,x=-3
Find the zeros of 10x^2+23x-21=0
The zeros of 10x^2+23x-21=0 are x= 7/10 ,x=-3