What is 0.5(9.11*10^{-31}) ?

The solution to 0.5(9.11*10^{-31}) is (911)/(200*10^{31)}

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simplify 0.5(9.11*10^{-31})

simplify

0.5 (9.11 \cdot 1 0^{- 31})

\frac{911}{200 \cdot 1 0 ^{31}}

Decimal Notation

4.555 E - 31

Solution steps

0.5 (9.11 \cdot 1 0^{- 31})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 31} = \frac{1}{1 0 ^{31}}

= 0.5 \cdot 9.11 \cdot \frac{1}{1 0 ^{31}}

9.11 \cdot \frac{1}{1 0 ^{31}} = \frac{911}{100 \cdot 1 0 ^{31}}

= 0.5 \cdot \frac{911}{100 \cdot 1 0 ^{31}}

0.5 \cdot \frac{911}{100 \cdot 1 0 ^{31}} = \frac{455.5}{1 0 ^{31} \cdot 100}

= \frac{455.5}{1 0 ^{31} \cdot 100}

\frac{455.5}{1 0 ^{31} \cdot 100} = \frac{4555}{1000 \cdot 1 0 ^{31}}

= \frac{4555}{1000 \cdot 1 0 ^{31}}

Factor the number:

4555 = 5 \cdot 911

= \frac{5 \cdot 911}{1000 \cdot 1 0 ^{31}}

Factor the number:

1000 = 5 \cdot 200

= \frac{5 \cdot 911}{5 \cdot 200 \cdot 1 0 ^{31}}

Cancel the common factor:

5

= \frac{911}{200 \cdot 1 0 ^{31}}

π^{(- 3)}

100 e^{- 0.5 (40)}

(54339) (1 + 0.07)^{- 9}

0.25 e^{- \frac{jπ}{4}} (4 j)

What is 0.5(9.11*10^{-31}) ?
The solution to 0.5(9.11*10^{-31}) is (911)/(200*10^{31)}