What are the solutions to the equation (y-5)^2=1 ?

The solutions to the equation (y-5)^2=1 are y=6,y=4

Find the zeros of (y-5)^2=1

The zeros of (y-5)^2=1 are y=6,y=4

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(y - 5)^{2} = 1

y = 6, y = 4

Solution steps

(y - 5)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 5 = 1 : y = 6

Solve

y - 5 = - 1 : y = 4

The solutions to the quadratic equation are:

y = 6, y = 4

2 x + 3 (5 x - 11) = 18

11 + 3 x \leq 17

∣ 7 x - 3 ∣ = - 3

r^{2} - 2 r - 1 = 0

(x + 3) \cdot (x - 5) = 0

What are the solutions to the equation (y-5)^2=1 ?
The solutions to the equation (y-5)^2=1 are y=6,y=4
Find the zeros of (y-5)^2=1
The zeros of (y-5)^2=1 are y=6,y=4