What is AB\Rightarrow B^cA^c ?

The solution to AB\Rightarrow B^cA^c is A^{c+1}B^{c+1}

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simplify AB\Rightarrow B^cA^c

simplify

A B \Rightarrow B^{c} A^{c}

A^{c + 1} B^{c + 1}

Solution steps

A B \Rightarrow B^{c} A^{c}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

A A^{c} = A^{1 + c}

= B \Rightarrow B^{c} A^{1 + c}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

B B^{c} = B^{1 + c}

=\Rightarrow B^{1 + c} A^{1 + c}

- (e^{- y})

e^{- 0.3 (5)}

e^{- 2 x} sin (2 x)

9 x^{5} (3 x^{2})

39 y^{4} y

What is AB\Rightarrow B^cA^c ?
The solution to AB\Rightarrow B^cA^c is A^{c+1}B^{c+1}