What is 10xy(e^{-(x^2+y^2)}) ?

The solution to 10xy(e^{-(x^2+y^2)}) is (10xy)/(e^{x^2+y^2)}

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simplify 10xy(e^{-(x^2+y^2)})

simplify

10 x y (e^{- (x^{2} + y^{2})})

\frac{10 x y}{e ^{x^{2} + y^{2}}}

Solution steps

10 x y (e^{- (x^{2} + y^{2})})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 10 \cdot \frac{1}{e ^{(x^{2} + y^{2})}} x y

Remove parentheses:

(a) = a

= 10 x y \frac{1}{e ^{x^{2} + y^{2}}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 10 x y}{e ^{x^{2} + y^{2}}}

Multiply the numbers:

1 \cdot 10 = 10

= \frac{10 x y}{e ^{x^{2} + y^{2}}}

(1222.84) (1 + 0.01486)^{- 8}

\frac{17}{7}

e^{- \frac{3}{x} y}

4 8^{4 x^{2}}

(n^{2})^{3^{^{'}}}

What is 10xy(e^{-(x^2+y^2)}) ?
The solution to 10xy(e^{-(x^2+y^2)}) is (10xy)/(e^{x^2+y^2)}