What is 2e^{-3t}(cos(4t)+sin(4t)) ?

The solution to 2e^{-3t}(cos(4t)+sin(4t)) is (2(cos(4t)+sin(4t)))/(e^{3t)}

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simplify 2e^{-3t}(cos(4t)+sin(4t))

simplify

2 e^{- 3 t} (cos (4 t) + sin (4 t))

\frac{2 ( cos ( 4 t ) + sin ( 4 t ) )}{e ^{3 t}}

Solution steps

2 e^{- 3 t} (cos (4 t) + sin (4 t))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{e ^{3 t}} (cos (4 t) + sin (4 t))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 ( cos ( 4 t ) + sin ( 4 t ) )}{e ^{3 t}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2 ( cos ( 4 t ) + sin ( 4 t ) )}{e ^{3 t}}

3.4575 x 1 0^{- 5}

50 e^{- 0.03 (60)}

0.3408 \cdot 1 0^{- 4}

reso l v er \frac{x ^{2} - 25}{x + 5}

b \cdot f

What is 2e^{-3t}(cos(4t)+sin(4t)) ?
The solution to 2e^{-3t}(cos(4t)+sin(4t)) is (2(cos(4t)+sin(4t)))/(e^{3t)}