What are the solutions to the equation -2+x-x^20.2-x=0 ?

The solutions to the equation -2+x-x^20.2-x=0 are x=-sqrt(10)i,x=sqrt(10)i

Find the zeros of -2+x-x^20.2-x=0

The zeros of -2+x-x^20.2-x=0 are x=-sqrt(10)i,x=sqrt(10)i

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- 2 + x - x^{2} 0.2 - x = 0

x = - 10 i, x = 10 i

Solution steps

- 2 + x - x^{2} \cdot 0.2 - x = 0

Multiply both sides by

10

- 2 x^{2} - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 ( - 2 ) ( - 20 )}{2 ( - 2 )}

Simplify

0^{2} - 4 (- 2) (- 20) : 410 i

x_{1, 2} = \frac{- 0 \pm 4 10 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 0 + 4 10 i}{2 ( - 2 )}, x_{2} = \frac{- 0 - 4 10 i}{2 ( - 2 )}

x = \frac{- 0 + 4 10 i}{2 ( - 2 )} : - 10 i

x = \frac{- 0 - 4 10 i}{2 ( - 2 )} : 10 i

The solutions to the quadratic equation are:

x = - 10 i, x = 10 i

9 x^{2} + 38 x y + 8 y^{2}

36 d^{2} + 5 d - 24

64 x^{3} - 125 y^{6}

∣ 3 - 3 x ∣ \leq 3

4 x^{2} + 31 x + 42 = 0

What are the solutions to the equation -2+x-x^20.2-x=0 ?
The solutions to the equation -2+x-x^20.2-x=0 are x=-sqrt(10)i,x=sqrt(10)i
Find the zeros of -2+x-x^20.2-x=0
The zeros of -2+x-x^20.2-x=0 are x=-sqrt(10)i,x=sqrt(10)i