What is e^{-x}(cos(x)+sin(x)) ?

The solution to e^{-x}(cos(x)+sin(x)) is (cos(x)+sin(x))/(e^x)

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simplify e^{-x}(cos(x)+sin(x))

simplify

e^{- x} (cos (x) + sin (x))

\frac{cos ( x ) + sin ( x )}{e ^{x}}

Solution steps

e^{- x} (cos (x) + sin (x))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{x}} (cos (x) + sin (x))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( cos ( x ) + sin ( x ) )}{e ^{x}}

1 \cdot (cos (x) + sin (x)) = cos (x) + sin (x)

= \frac{cos ( x ) + sin ( x )}{e ^{x}}

(x^{5} y a) (x^{4} y^{3})

e^{k} e^{t}

2.31 \cdot 1 0^{- 6}

6 70 0^{4}

\frac{3 ^{0.2}}{5 ^{0.2}}

What is e^{-x}(cos(x)+sin(x)) ?
The solution to e^{-x}(cos(x)+sin(x)) is (cos(x)+sin(x))/(e^x)