What is (x^1,)(x^2,)(y^2)(y^1) ?

The solution to (x^1,)(x^2,)(y^2)(y^1) is y^3(,x^1)(,x^2)

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simplify (x^1,)(x^2,)(y^2)(y^1)

simplify

(x^{1},) (x^{2},) (y^{2}) (y^{1})

y^{3} (, x^{1}) (, x^{2})

Solution steps

(x^{1},) (x^{2},) (y^{2}) (y^{1})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{2} y^{1} = y^{2 + 1}

= (x^{1},) (x^{2},) y^{2 + 1}

Add the numbers:

2 + 1 = 3

= (x^{1},) (x^{2},) y^{3}

e (e^{x + y + z})

(x^{2} y^{3}) (2 x y)

(((\frac{4}{7})^{x})^{2})^{4}

3 (3)^{2} (0.002)

2.513 (1 0^{- 5})

What is (x^1,)(x^2,)(y^2)(y^1) ?
The solution to (x^1,)(x^2,)(y^2)(y^1) is y^3(,x^1)(,x^2)