What is e^{-t(b+s)}sin(wt) ?

The solution to e^{-t(b+s)}sin(wt) is (sin(tw))/(e^{t(s+b))}

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simplify e^{-t(b+s)}sin(wt)

simplify

e^{- t (b + s)} sin (wt)

\frac{sin ( tw )}{e ^{t (s + b)}}

Solution steps

e^{- t (b + s)} sin (wt)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{t (s + b)}} sin (tw)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot sin ( wt )}{e ^{t (b + s)}}

Multiply:

1 \cdot sin (wt) = sin (wt)

= \frac{sin ( tw )}{e ^{t (s + b)}}

x + 6 \cdot x + 6 + h

\frac{2 3 ^{18}}{3 5 ^{18}}

(1 + e^{2 x}) e^{- x} d x

e^{- 0.208}

7 0, 2 x^{0.28} 0.2

What is e^{-t(b+s)}sin(wt) ?
The solution to e^{-t(b+s)}sin(wt) is (sin(tw))/(e^{t(s+b))}