What are the solutions to the equation x^2+12x=-27 ?

The solutions to the equation x^2+12x=-27 are x=-3,x=-9

Find the zeros of x^2+12x=-27

The zeros of x^2+12x=-27 are x=-3,x=-9

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x^{2} + 12 x = - 27

x = - 3, x = - 9

Solution steps

x^{2} + 12 x = - 27

Move

27

to the left side

x^{2} + 12 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 27 = 6

x_{1, 2} = \frac{- 12 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 6}{2 \cdot 1}, x_{2} = \frac{- 12 - 6}{2 \cdot 1}

x = \frac{- 12 + 6}{2 \cdot 1} : - 3

x = \frac{- 12 - 6}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 3, x = - 9

x^{4} y^{3} + 7 x^{2} y - 3 x^{3} y^{3}

(a + 16)^{2} = 16

s^{2} + 7 s t - 30 t^{2}

4 v^{2} + 15 v + 9

x^{3} - 9 x^{2} + 5 x - 45

What are the solutions to the equation x^2+12x=-27 ?
The solutions to the equation x^2+12x=-27 are x=-3,x=-9
Find the zeros of x^2+12x=-27
The zeros of x^2+12x=-27 are x=-3,x=-9