What is (2.9*10^{-19})(3712) ?

The solution to (2.9*10^{-19})(3712) is (841)/(5^{20)*8192}

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simplify (2.9*10^{-19})(3712)

simplify

(2.9 \cdot 1 0^{- 19}) (3712)

\frac{841}{5 ^{20} \cdot 8192}

Solution steps

(2.9 \cdot 1 0^{- 19}) (3712)

Apply rule:

(a) = a

(3712) = 3712

= 2.9 \cdot 1 0^{- 19} \cdot 3712

Multiply the numbers:

2.9 \cdot 3712 = 10764.8

= 10764.8 \cdot 1 0^{- 19}

= 1 0^{- 19} \cdot 10764.8

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 19} = \frac{1}{1 0 ^{19}}

= \frac{1}{1 0 ^{19}} \cdot 10764.8

\frac{1}{1 0 ^{19}} \cdot 10764.8 = \frac{10764.8}{1 0 ^{19}}

= \frac{10764.8}{1 0 ^{19}}

\frac{10764.8}{1 0 ^{19}} = \frac{107648}{10 \cdot 1 0 ^{19}}

= \frac{107648}{10 \cdot 1 0 ^{19}}

10 \cdot 1 0^{19} = 1 0^{20}

= \frac{107648}{1 0 ^{20}}

Factor

107648 : 2^{7} \cdot 841

= \frac{2 ^{7} \cdot 841}{1 0 ^{20}}

Factor

1 0^{20} : 2^{20} \cdot 5^{20}

= \frac{2 ^{7} \cdot 841}{2 ^{20} \cdot 5 ^{20}}

\frac{2 ^{7}}{2 ^{20}} = \frac{1}{2 ^{13}}

= \frac{841}{2 ^{13} \cdot 5 ^{20}}

2^{13} = 8192

= \frac{841}{5 ^{20} \cdot 8192}

(x)^{5 x}

(x - 3)^{5} (2 x + 1)^{5}

\frac{e ^{3}}{e ^{- x}}

131.38 e^{- 0.434 (1.4)}

x^{\frac{1}{3}} y^{\frac{1}{3}}

What is (2.9*10^{-19})(3712) ?
The solution to (2.9*10^{-19})(3712) is (841)/(5^{20)*8192}