What is the derivative of 2sqrt(d(y(d,x-x))) ?

The derivative of 2sqrt(d(y(d,x-x))) is 2*1/(2sqrt(d({y)(d,x)-x))}d(derivative of {y}(d,x)-1)

What is the first derivative of 2sqrt(d(y(d,x-x))) ?

The first derivative of 2sqrt(d(y(d,x-x))) is 2*1/(2sqrt(d({y)(d,x)-x))}d(derivative of {y}(d,x)-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 d (y (d, x) - x))

2 \cdot \frac{1}{2 d ( y ( d , x ) - x )} d (\frac{d}{d x} (y (d, x)) - 1)

Solution steps

\frac{d}{d x} (2 d (y (d, x) - x))

Treat

d

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (d (y (d, x) - x))

Apply the chain rule:

\frac{1}{2 d ( y ( d , x ) - x )} \frac{d}{d x} (d (y (d, x) - x))

= \frac{1}{2 d ( y ( d , x ) - x )} \frac{d}{d x} (d (y (d, x) - x))

\frac{d}{d x} (d (y (d, x) - x)) = d (\frac{d}{d x} (y (d, x)) - 1)

= 2 \cdot \frac{1}{2 d ( y ( d , x ) - x )} d (\frac{d}{d x} (y (d, x)) - 1)

\frac{y}{x} (2 - 1)

(32 - x)^{2} \cdot (16 - 2 x)^{2}

2^{- 3 4^{3}}

- 3 x^{4} y^{4}

What is the derivative of 2sqrt(d(y(d,x-x))) ?
The derivative of 2sqrt(d(y(d,x-x))) is 2*1/(2sqrt(d({y)(d,x)-x))}d(derivative of {y}(d,x)-1)
What is the first derivative of 2sqrt(d(y(d,x-x))) ?
The first derivative of 2sqrt(d(y(d,x-x))) is 2*1/(2sqrt(d({y)(d,x)-x))}d(derivative of {y}(d,x)-1)