What is ((x+3))/8 >((x-2))/3 ?

The solution to ((x+3))/8 >((x-2))/3 is x<5

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((x+3))/8 >((x-2))/3

\frac{( x + 3 )}{8} > \frac{( x - 2 )}{3}

x < 5

Interval Notation

(- \infty, 5)

Solution steps

\frac{( x + 3 )}{8} > \frac{( x - 2 )}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(x + 3) \cdot 3 > 8 (x - 2)

Expand

(x + 3) \cdot 3 : 3 x + 9

Expand

8 (x - 2) : 8 x - 16

3 x + 9 > 8 x - 16

Move

9

to the right side

3 x > 8 x - 25

Move

8 x

to the left side

- 5 x > - 25

Multiply both sides by

- 1

5 x < 25

Divide both sides by

5

x < 5

(x - 7)^{2} = 49

∣ 5 x - 1 ∣ < 11

3 x^{2} + 5 x + 11 < 0

∣ 0 ∣

2 ∣ ln (x) ∣ - 6 = 0